Dear Angela,
in order to do this, the setdefault function of the dictionaries is very
useful.
For example:
mydict = {}
mylist = mydict.setdefault(mykey, [])
mylist.append(myvalue)
"setdefault" either returns the already existing list or sets a new list
for the key and returns it.
Regards,
Benoit Thiell.
On Fri, 1 Aug 2008, Marc Tompkins wrote:
On Thu, Jul 31, 2008 at 8:16 PM, Angela Yang <[EMAIL PROTECTED]> wrote:
Hi,
I have a list of values for one key. How do I specify this data
structure?
First tried,
collection = []
collection['abby'].append('apprentice1')
collection['abby'].append('apprentice2')
That did not work because list index is not numeric.
But for dictionaries, it is key - value pairs. But I need key ->
multiple values.
Do you have some example how to specify this?
Angela
Each "value" can, itself, be a container - a tuple, a list, or another
dictionary.
dictTuple = {"a":(1,2,3), "b":(4,5,6)}
dictList = {"a":[1,2,3], "b":[4,5,6]}
dictDict = {"a":{"c":"1","d":"2","e":"3"}, "b":{"f":"4","g":"5","h":"6"}}
Retrieving values:
valValue = dictTuple["a"][0] # 1
valValue = dictTuple["b"][2] # 6
Lists work just the same:
valValue = dictList["a"][0] # 1
valValue = dictList["b"][2] # 6
Dictionaries are, well, like dictionaries:
valValue = dictDict["a"]["c"] # 1
valValue = dictDict["b"]["h"] # 6
Hope that helps....
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