Straight forward method would be...
>>> a=[[1],[2]]
>>> b={}
>>> for x in range(len(a)):
... b[x] = a[x]
...
>>> a
[[1], [2]]
>>> b
{0: [1], 1: [2]}
>>>
regards,
shantanoo
On 21-Sep-08, at 11:36 AM, Dinesh B Vadhia wrote:
Hi! Say, I've got a numpy array/matrix of the form:
[[1 6 1 2 3]
[4 5 4 7 0]
[2 0 8 0 2]
[8 2 6 3 0]
[0 7 0 3 5]
[8 0 3 0 6]
[8 0 0 2 2]
[3 1 0 4 0]
[5 0 8 0 0]
[2 1 0 5 6]]
And, I want to create a dictionary of rows (as the keys) mapped to
lists of non-zero numbers in that row ie.
dictionary_non-zeros = {
0: [1 6 1 2 3]
1: [4 5 4 7]
2: [2 8 2]
...
9: [2 1 5 6]
}
How do I do this?
Thanks!
Dinesh
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http://mail.python.org/mailman/listinfo/tutor
