On Tue, Oct 21, 2008 at 01:36, Kent Johnson <[EMAIL PROTECTED]> wrote: >> somelist = ['Test1', 'Text2', ['1', '2'], 'Text3'] >> templist = [] >> for x in range(len(somelist[2])): >> templist.append([somelist[0], somelist[1], somelist[2][x], somelist[3]]) > > Is it always just the third item that is a list? If so I think your > solution is not too bad.
The actual list is 12 items long (python lenght) and the 6, 7 and 8th item should be lists after I split them. A sanitized example: ['SOMENAME', '1234567890', '"TEXT1"', 'TEXT2', '59', '', '10/03;10/15', '10/09;10/20', '1;70', '', '', ''] > or use a list comprehension: > templist = [ somelist[0:2] + [x] + somelist[3:] for x in somelist ] This did not work but the below did ;-) templist = [ somelist[:1] + [x] + somelist[3:] for x in somelist[2] ] It gave me some great pointers on how to handle this. Thanks Sander _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
