Omer wrote:
Bob, I tried your way.
>>> import re
>>> urlMask = r"http://[\w\Q./\?=\R]+(<br>)?"
>>> text=u"Not working
example<br>http://this.is.a/url?header=null<br>And another
line<br>http://and.another.url";
>>> re.findall(urlMask,text)
[u'<br>', u'']
Oops I failed to notice you were using findall. Kent explained it.
Another way to fix it is to make (<br>) a non-group: (?:<br>)
--
Bob Gailer
Chapel Hill NC
919-636-4239
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