eShopping wrote:
Bob

I am trying to read UNFORMATTED files. The files also occur as formatted files and the format string I provided is the string used to write the formatted version. I can read the formatted version OK. I (naively) assumed that the same format string was used for both files, the only differences being whether the FORTRAN WRITE statement indicated unformatted or formatted.

WRITE UNFORMATTED dump memory to disk with no formatting. That is why we must do some analysis of the file to see where the data has been placed, how long the floats are, and what "endian" is being used.

I'd like to examine the file myself. We might save a lot of time and energy that way. If it is not very large would you attach it to your reply. If it is very large you could either copy just the first 1000 or so bytes, or send the whole thing thru www.yousendit.com.

At 21:41 03/02/2009, bob gailer wrote:
First question: are you trying to work with the file written UNFORMATTED? If so read on.

Well, did you read on? What reactions do you have?

eShopping wrote:

Data format:

TIME      1  F  0.0
DISTANCE 10  F  0.0 1.0 2.0 3.0 4.0 5.0 6.0 7.0 8.0 9.0

F=float, D=double, L=logical, S=string etc


The first part of the file should contain a string (eg "TIME"),
an integer (1) and another string (eg "F") so I tried using

import struct
in_file = open(file_name+".dat","rb")
data = in_file.read()
items = struct.unpack('sds', data)

Now I get the error

error: unpack requires a string argument of length 17

which has left me completely baffled!

Did you open the file with mode 'b'? If not change that.

You are passing the entire file to unpack when you should be giving it only the first "line". That's why is is complaining about the length. We need to figure out the lengths of the lines.

Consider the first "line"

TIME      1  F  0.0

There were (I assume) 4 FORTRAN variables written here: character integer character float. Without knowing the lengths of the character variables we are at a loss as to what the struct format should be. Do you know their lengths? Is the last float or double?

Try this: print data[:40] You should see something like:

TIME...\x01\x00\x00\x00...F...\x00\x00\x00\x00...DISTANCE...\n\x00\x00\x00

where ... means 0 or more intervening stuff. It might be that the \x01 and the \n are in other places, as we also have to deal with "byte order" issues.

Please do this and report back your results. And also the FORTRAN variable types if you have access to them.

Apologies if this is getting a bit messy but the files are at a remote location and I forgot to bring copies home. I don't have access to the original FORTRAN program so I tried to emulate the reading the data using the Python script below. AFAIK the FORTRAN format line for the header is (1X, 1X, A8, 1X, 1X, I6, 1X, 1X, A1). If the data following is a float it is written using n(1X, F6.2) where n is the number of records picked up from the preceding header.

# test program to read binary data

import struct

# create dummy data

data = []
for i in range(0,10):
    data.append(float(i))

# write data to binary file

b_file = open("test.bin","wb")

b_file.write("  %8s  %6d  %1s\n" % ("DISTANCE", len(data), "F"))
for x in data:
    b_file.write(" %6.2f" % x)

You are still confusing text vs binary. The above writes text regardless of the file mode. If the FORTRAN file was written UNFORMATTED then you are NOT emulating that with the above program. The character data is read back in just fine, since there is no translation involved in the writing nor in the reading. The integer len(data) is being written as its text (character) representation (translating binary to text) but being read back in without translation. Also all the floating point data is going out as text.

The file looks like (where b = blank) (how it would look in notepad):

bbDISTANCEbbbbbb10bFbbb0.00bbb1.00bbb2.00 If you analyze this with 2s8s2si2s1s you will see 2s matches bb, 8s matches DISTANCE, 2s matches bb, i matches bbbb. (\x40\x40\x40\x40). The i tells unpack to shove those 4 bytes unaltered into a Python integer, resulting in 538976288. You can verify that:

>>> struct.unpack('i', '    ')
(538976288,)

Please either assure me you understand or are prepared for a more in depth tutorial.
b_file.close()

# read back data from file

c_file = open("test.bin","rb")

data = c_file.read()
start, stop = 0, struct.calcsize("2s8s2si2s1s")

items = struct.unpack("2s8s2si2s1s",data[start:stop])
print items
print data[:40]

I'm pretty sure that when I tried this at the other PC there were a bunch of \x00\x00 characters in the file but they don't appear in NotePad ... anyway, I thought the Python above would unpack the data but items appears as

('  ', 'DISTANCE', '  ', 538976288, '10', ' ')

which seems to be contain an extra item (538976288)

Alun Griffiths


--
Bob Gailer
Chapel Hill NC
919-636-4239

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Tutor maillist  -  Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor



--
Bob Gailer
Chapel Hill NC
919-636-4239
_______________________________________________
Tutor maillist  -  Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor

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