A regex isn't always the best solution: >>> a=''.join(chr(n) for n in range(256)) >>> a '\x00\x01\x02\x03\x04\x05\x06\x07\x08\t\n\x0b\x0c\r\x0e\x0f\x10\x11\x12\x13\x14\x15\x16\x17\x18\x19\x1a\x1b\x1c\x1d\x1e\x1f !"#$%&\'()*+,-./0123456789:;<=>?...@abcdefghijklmnopqrstuvwxyz[\\]^_`abcdefghijklmnopqrstuvwxyz{|}~\x7f\x80\x81\x82\x83\x84\x85\x86\x87\x88\x89\x8a\x8b\x8c\x8d\x8e\x8f\x90\x91\x92\x93\x94\x95\x96\x97\x98\x99\x9a\x9b\x9c\x9d\x9e\x9f\xa0\xa1\xa2\xa3\xa4\xa5\xa6\xa7\xa8\xa9\xaa\xab\xac\xad\xae\xaf\xb0\xb1\xb2\xb3\xb4\xb5\xb6\xb7\xb8\xb9\xba\xbb\xbc\xbd\xbe\xbf\xc0\xc1\xc2\xc3\xc4\xc5\xc6\xc7\xc8\xc9\xca\xcb\xcc\xcd\xce\xcf\xd0\xd1\xd2\xd3\xd4\xd5\xd6\xd7\xd8\xd9\xda\xdb\xdc\xdd\xde\xdf\xe0\xe1\xe2\xe3\xe4\xe5\xe6\xe7\xe8\xe9\xea\xeb\xec\xed\xee\xef\xf0\xf1\xf2\xf3\xf4\xf5\xf6\xf7\xf8\xf9\xfa\xfb\xfc\xfd\xfe\xff' >>> b=''.join(n for n in a if ord(n) >= 32 and ord(n) <= 126) >>> b ' !"#$%&\'()*+,-./0123456789:;<=>?...@abcdefghijklmnopqrstuvwxyz[\\]^_`abcdefghijklmnopqrstuvwxyz{|}~'
-Mark "Dinesh B Vadhia" <dineshbvad...@hotmail.com> wrote in message news:col103-ds55714842811febeb4a97ca3...@phx.gbl... I want a regex to remove control characters (< chr(32) and > chr(126)) from strings ie. line = re.sub(r"[^a-z0-9-';.]", " ", line) # replace all chars NOT A-Z, a-z, 0-9, [-';.] with " " 1. What is the best way to include all the required chars rather than list them all within the r"" ? 2. How do you handle the inclusion of the quotation mark " ? Cheers Dinesh ------------------------------------------------------------------------------ _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
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