"jessica cruz" <jessica06c...@yahoo.com> wrote
I just started learning python an I'm currently working on this
program.
The purpose of this program is to read a string of letters from user
input and print out all the words which are anagrams of the input
string.
Where you define an anagram to be a word that is in wordlist I assume?
it says that there is an error "invalid syntax" but I can't figure
out where.
Always send us the full error message, it usually tells us where
to look, which is easier than reading the full program!
#this reads all of the words in the file into a list
infile = open('/afs/cats/courses/cmps012a-cm/pa1/wordList.txt')
wdcount = int(infile.readline()) #first item is count of all the
words
You do not use this, why bother?
word_list = infile.readlines()
wordList = []
# code that will be compared will be a histogram type code with
frequency
# characters
def code(w):
hist = []
chars = list(w)
chars.sort()
for letter in chars:
if not letter in hist: # when the letter is not already in
hist,
hist.extend([letter, str(w.count(letter))]) # its added
to hist along with its freq.
else:
continue
coding = "".join(hist) # then they are joined as one string
return coding
# new list is made with words in word_list followed by its code
for word in word_list:
wordList.append(word)
wordList.append(code(word[:(len(word)-2)]))
word[:len(word)-2] could be written much more clearly as
word[:-2]
while True:
word1 = raw_input('Enter word:')
word = word1.lower()
sig = code(word)
i = 1
if sig in wordList:
print "Anagrams:"
while i <= len(wordList): # when the sig of the inputed word is in
the word list,
if sig == wordList[i]
This looks like the syntax error - no colon.
I stopped here.
I think there are easier ways to do this!
--
Alan G
Author of the Learn to Program web site
http://www.alan-g.me.uk/l2p/
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