2009/3/31 james carnell <jimcarn...@yahoo.com>: > for row in range(25,31,1): > for col in range(10,12, 0.3): #<- Crash Bang doesn't work 0.3 = zero = > infinite loop? > [...] > is there no way to do it with a range function (and have it still look like > you're not on crack)?
Well, you could do this: >>> [float(x)/3 for x in range(30, 37)] [10.0, 10.333333333333334, 10.666666666666666, 11.0, 11.333333333333334, 11.666666666666666, 12.0] Or even: >>> [math.floor(10*float(x)/3)/10 for x in range(30, 37)] [10.0, 10.300000000000001, 10.6, 11.0, 11.300000000000001, 11.6, 12.0] However, the builtin range() only works with integers. I think there is a range() function in the python cookbook that will do fractional step sizes. But really, there's nothing wrong with your while loop. -- John. _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor