"Dominique" <mydom...@gmail.com> wrote
I tried several other ways without any success:
subprocess.Popen(args = ["notepad++.exe", filename])
subprocess.Popen(args = ["C:\Program Files\Notepad++\notepad++.exe",
filename])
I wonder if it is due to the location of the softwares.
In a way. I think it's because you are using single backslashes.
You need to make the command a raw string by putting an r in front.:
subprocess.Popen([r"C:\Program Files\Notepad++\notepad++.exe", filename])
Otherwise Python gets confused by \n and thinks its a newline character
If not is thre an API to the editor, for example Windows editors
may have a COM interface that you could access.
Do you mean that it is not always possible to open another software from
python,
notably if the software doesn't have a COM interface ?
You can always open the program but some programs may not take
command line arguments to open a file. Thuis you need to drive them
via COM to effectively use the File->Open menu option from Python.
Fortunately most editors will accept a command line filename so its
only rarely an issue for editors. But things like statistics [packages,
graphics editors etc can be more difficult.
ed = os.getenv('EDITOR')
vi = os.getenv('VISUAL')
os.getenv is always None,
Presumably you don;t have either EDITOR or VISUAL defined.
What if you try
os.getenv('PATH')
That should return something.
which may be correct since I am on Windows ?
No, getenv() works on any OS, although Unix tends to use environment
variables much more than Windows, which favours the registry.
Alan G.
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