On 5/10/2009 3:48 PM Emilio Casbas said...
Hello,
I have some problems testing keys not existent in a dictionary.
The code works testing existent keys with his corresponding value, but
If I enter a not existent key, an exception is raised.
How can I control the not existent key and assign him a default value?
u...@cipher:~/project/programming/python$ python3.0 test.py
¿What is your name? KEY-NOT-EXISTENT
Good Morning KEY-NOT-EXISTENT
¿Which is the secret word? any
Traceback (most recent call last):
File "test.py", line 30, in <module>
while not correct_password(name,guess,dictionary):
File "test.py", line 8, in correct_password
if (is_in_dict and password == dict[nombre.capitalize()]):
KeyError: 'KEY-NOT-EXISTENT'
-relevant code snippet-
dictionary = {'Mark': 'python', 'Dave': 'java', 'Ane': 'C++', 'default':'pass'}
def correct_password(name,password,dict):
if (not is_in_dict and password == dict['default']):
Both here...
return 1
elif (is_in_dict and password == dict[nombre.capitalize()]):
... and here you're not testing the inputs, you're testing if is_in_dict
_is_ (which of course it is as it's defined and ergo is) -- you need
to pass it your parameters, ie, 'is_in_dict(nombre,dictionary)'
return 1
return 0
def is_in_dict(nom,dict):
also -- it's not a good ides to shadow built-in names -- better to use a
different one like n_dict
HTH,
Emile
for n in dict:
if nom.lower() == n.lower():
return 1
return 0
-end relevant code snippet-
Regards
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_______________________________________________
Tutor maillist - [email protected]
http://mail.python.org/mailman/listinfo/tutor
