Kent Johnson wrote:
On Thu, May 14, 2009 at 3:34 AM, Timo <timomli...@gmail.com> wrote:
Emile van Sebille schreef:
If this is always the case you can use the sort method of lists, then
relocate the last entry to the front --
a = [4, 6, 'word', 3, 9]
a.sort()
a.insert(0,a.pop())
a
['word', 3, 4, 6, 9]
Thanks all for your answers. I think I will go for this solution (should
have come to it myself).
I don't think this will be reliable. IIUC unlike objects are compared
by ID, so it is not guaranteed that strings will sort after numbers.
The ability to compare unlike objects at all is considered a
mis-feature and has been removed in Python 3:
http://mail.python.org/pipermail/python-dev/2004-June/045111.html
Python 3.0.1 (r301:69556, Feb 14 2009, 22:08:17)
[GCC 4.0.1 (Apple Computer, Inc. build 5367)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
a = [4, 6, 'word', 3, 9]
a.sort()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: unorderable types: str() < int()
Kent
_______________________________________________
Tutor maillist - Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor
Why not be safe and generate 2 lists and merge them afterwards like:
>>> numeric_list, string_list = [], []
>>> a=[4,6,'word',3,9]
>>> [numeric_list.append(int(element)) if element.isdigit() else
string_list.append(element) for element in map(str,a)]
[None, None, None, None, None]
>>> numeric_list.sort(); string_list.sort();
>>> numeric_list, string_list
([3, 4, 6, 9], ['word'])
>>> string_list.extend(numeric_list)
>>> string_list
['word', 3, 4, 6, 9]
--
Kind Regards,
Christian Witts
_______________________________________________
Tutor maillist - Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor
