On Fri, May 15, 2009 at 12:46 AM, R K <wolf85boy2...@yahoo.com> wrote: > Gurus, > > I'm trying to write a fairly simple script that finds the number of hours / > minutes / seconds between now and the next Friday at 1:30AM. > > I have a few little chunks of code but I can't seem to get everything to > piece together nicely. > > import datetime,time > now = datetime.datetime.now() > > i = 0 > dayOfWeek = datetime.datetime.now().strftime( '%a' ) > while dayOfWeek != 'Fri': > delta = datetime.timedelta( days = i ) > tom = ( now + delta ).strftime( '%a' ) > if tom != 'Fri': > i = i + 1 > else: > print i > print tom > break > > So with this code I can determine the number of days until the next Friday > (if it's not Friday already).
This could be simpler. I would write nextFriday = datetime.datetime(now.year, now.month, now.day, 1, 30, 0) while nextFriday.weekday() != 4: nextFriday += datetime.timedelta(days=1) Note the use of datetime attributes instead of relying on strftime(). What do you want the answer to be if you run the script at 1am Friday? at 2am Friday? If you want the next Friday in both cases, you could write this as nextFriday = datetime.datetime(now.year, now.month, now.day, 1, 30, 0) nextFriday += datetime.timedelta(days=1) # Make sure to get a Friday in the future while nextFriday.weekday() != 4: nextFriday += datetime.timedelta(days=1) Kent _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
