"NTB" <ntb1...@gmail.com> wrote
array [['Food 1', 'Nutrient 1', 0.9], ['Food 1', 'Nutrient 2', 0.2], ['Food 2', 'Nutrient 1', 0.55], ['Food 2', 'Nutrient 2', 0.11]]into a new array that looks like this: array [['Food 1', 0.9, 0.2], ['Food 2', 0.55, 0.11]]
I'd probably use an intermediate dictionary:
a = [['F1','ggh',0.9],['F1','gh',0.5],['f2','dsd',0.7]] d = {} for r in a:
... if r[0] in d: d[r[0]].append(r[2]) ... else: d[r[0]] = [r[0],r[2]] ...
new = [v for k,v in d.items()] new
[['F1', 0.9, 0.5], ['f2', 0.6999]]
There may be a more elegant way to handle the if/else but its too early to think of one :-)
HTH, -- Alan Gauld Author of the Learn to Program web site http://www.alan-g.me.uk/
_______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
