Hi Robert, Thanks for the link. However, I am looking for eliminating consecutive duplicates rather than all duplicates - my example wasn't clear, apologies for that.
x=[1,1,1,3,2,2,2,4,4,2,2] [1 ,3 ,2 ,4 ,2 ] 2009/6/18 Robert Berman <berma...@cfl.rr.com>: > This might help: http://code.activestate.com/recipes/52560/ > > Robert > > > On Thu, 2009-06-18 at 15:15 +0200, karma wrote: >> I was playing around with eliminating duplicates in a list not using >> groupby. From the two solutions below, which is more "pythonic". >> Alternative solutions would be welcome. >> >> Thanks >> >> x=[1,1,1,3,2,2,2,2,4,4] >> >> [v for i,v in enumerate(x) if x[i]!=x[i-1] or i==0] >> >> [x[i] for i in range(len(x)-1) if i==0 or x[i]!=x[i-1]] >> >> output: >> [1, 3, 2, 4] >> _______________________________________________ >> Tutor maillist - tu...@python.org >> http://mail.python.org/mailman/listinfo/tutor > > _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
