On Fri, Jun 26, 2009 at 2:28 PM, Dinesh B
Vadhia<dineshbvad...@hotmail.com> wrote:
> Say, you create an array['i'] for signed integers (which take a minimum 2
> bytes). A calculation results in an integer that is larger than the range
> of an 'i'. Normally, Python will convert an 'i' to a 4-byte 'l' integer.
> But, does the same apply for an array ie. does Python dynamically adjust
> from array['i'] to array['l'']?
No. It's easy enough to try:
In [1]: import array
In [2]: a = array.array('i')
In [3]: a.itemsize
Out[3]: 4
In [5]: a.append(1)
In [6]: a
Out[6]: array('i', [1])
In [7]: x = 2**33
In [8]: x
Out[8]: 8589934592L
In [9]: a[0] = x
---------------------------------------------------------------------------
OverflowError Traceback (most recent call last)
C:\Project\Mango\<ipython console> in <module>()
OverflowError: long int too large to convert to int
Kent
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