On 7/3/2009 12:09 PM Dinesh B Vadhia said...
I'm suffering from brain failure (or most likely just being brain less!)
and need help to create a list comprehension for this problem:
d is a list of integers: d = [0, 8, 4, 4, 4, 7, 2, 5, 1, 1, 5, 11, 11,
1, 6, 3, 5, 6, 11, 1]
Want to create a new list that adds the current number and the prior
number, where the prior number is the accumulation of the previous
numbers ie.
[ sum(d[:j]) for j in range(len(d)) ][1:]
Emile
dd = [0, 8, 12, 16, 20, 27, 29, 34, 35, 36, 41, 52, 63, 64, 70, 73, 78,
84, 95, 96]
A brute force solution which works is:
>>> dd = []
>>> y = d[0]
>>> for i, x in enumerate(d):
>>> y += x
>>> dd.append(y)
Is there a list comprehension solution?
Dinesh
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