shellc...@juno.com wrote:
I want to write a code that allows me to input a phrase and calculate the
number of vowels twice. once with the for loop and second with the while loop.I
can get the for loop to work but, not the while loop. this is my code and
response.
#demo for loop, and while loop
phrase = raw_input("enter your phrase:")
VOWELS = "aeiou"
number = 0
for letter in phrase:
if letter.lower() in VOWELS:
number = number +1
else:
pass
print "Number of vowels =",number
raw_input("Press the enter key to continue.")
index = 0
while index < len(phrase):
if phrase[index] in VOWELS:
index = index +1
print "number of vowels" ,index
enter your phrase:tell me your name
Number of vowels = 0
Number of vowels = 1
Number of vowels = 1
Number of vowels = 1
Number of vowels = 1
Number of vowels = 1
Number of vowels = 2
Number of vowels = 2
Number of vowels = 2
Number of vowels = 3
Number of vowels = 4
Number of vowels = 4
Number of vowels = 4
Number of vowels = 4
Number of vowels = 5
Number of vowels = 5
Number of vowels = 6
Press the enter key to continue.
____________________________________________________________
Best Weight Loss Program - Click Here!
http://thirdpartyoffers.juno.com/TGL2141/fc/BLSrjpTFoYcWEqYCcbHEaFPTq8jdS8V2cC4YnTjQIbcZlB9fvaKI0BwmgT2/
_______________________________________________
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
http://mail.python.org/mailman/listinfo/tutor
Your while loop will continue indefinitely if the phrase is not
completely vowels. What you should do is remember to increment the
value of index regardless of if the letter is a vowel of not:
VOWELS = 'aeiouAEIOU'
cnt = 0
index = 0
while index < len(phrase):
if phrase[index] in VOWELS:
cnt += 1
print 'Number of Vowels = %s' %cnt
index += 1
--
Kind Regards,
Christian Witts
_______________________________________________
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
http://mail.python.org/mailman/listinfo/tutor
