Hi Emile, that functions requires a filename/path. Just like this one (for images)
http://docs.python.org/library/imghdr.html Ok, i don't have a filename. I get the file from a BLOB in a db. Any idea? Thankyou for your precious help. 2009/9/18 Emile van Sebille <em...@fenx.com>: > On 9/18/2009 10:05 AM ad...@gg-lab.net said... >> >> Hi, >> >> i'm putting file in a DB as BLOB entries. To serve them, i need to >> take Content-Type headers. >> >> So, i'm looking for a function that returnes the filetype, given a data >> str. >> >> I've found many other topics like this in python mail-archive, but any >> of them contains the solution. >> >> Can you help me, please? > > I'd take a look at python-magic at > http://hupp.org/adam/hg/python-magic/file/d3cd83e5a773 where the example > shows that you can do: > > # For MIME types >>>> mime = magic.Magic(mime=True) >>>> mime.from_file("testdata/test.pdf") > 'application/pdf' > > > HTH, > > Emile > > > > > >> >> Thankyou! >> _______________________________________________ >> Tutor maillist - tu...@python.org >> To unsubscribe or change subscription options: >> http://mail.python.org/mailman/listinfo/tutor >> > > _______________________________________________ > Tutor maillist - tu...@python.org > To unsubscribe or change subscription options: > http://mail.python.org/mailman/listinfo/tutor > _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
