Yes, Robert, that does it! Thanks a lot! Have a nice weekend! Jose
On Saturday 28 November 2009 10:54:56 am Robert Johansson wrote: > Hi! > I want to process corresponding elements of two lists, sequentially. Call > the > lists list1 and list2, and assume they have equal lengths. I can do > something > like > > for index in range(len(list1)): > process(list1[index], list2[index]) > > But I find it somehow rather ugly, because we generate yet another an list > for > the index, when we already have the two we want to process. I know we can > use > xrange, but still I find it awkward... > > Instead of the above snippet, I am considering something like > > while list1: > process(list1.pop(), list2.pop()) > > But this has the side effect of emptying both lists, which may not be > convenient. Of course we can make backup copies of the lists if needed, but > we > are then recovering the previous method ugliness... > > Maybe enumerate is what you are looking for? > > list1=range(10) > list2=range(10,20) > for index, element in enumerate(list1): > print element, list2[index] > > /Robert > _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor