-----Original Message-----
From: tutor-bounces+bermanrl=cfl.rr....@python.org
[mailto:tutor-bounces+bermanrl=cfl.rr....@python.org] On Behalf Of Ken G.
Sent: Sunday, January 31, 2010 10:41 AM
To: tutor@python.org
Subject: [Tutor] Future Appointments...
Below is a program to determine when my next appointment is. Line
numbers are provided for reference only.
01 import time, datetime, sys
02 from datetime import date
03 today = date.today()
04 print
05 print "Today date is:", today
06 todaystr = str(today)
07 print
08 print "Corrected date format is:",
09 print todaystr[ 5: 7], todaystr[ 8:10], todaystr[ 0: 4]
10 print
11 future = raw_input("Next appointment is in how many days? "),
12 print
13 difference1 = datetime.timedelta(days=1)
14 datestring = str(today + difference1)
15 print "Next appointment after that is:",datestring
16 print
17 print "Corrected date format for next appointment is:",
18 print datestring[ 5: 7], datestring[ 8:10], datestring[ 0: 4]
19 sys.exit()
In answering the question in line 11 as to when is my next appointment,
I would answer "3" (for 2/3/2010) but how do I change "days=1" at end of
line 13 to "days=3" so that datestring would read "2010-02-03" instead
of "2010-02-01" as presented above?
TIA,
Ken
*****************************************************************
Hi Ken,
I slightly altered your program. I think this is what you asked for. It will
work for n number of days; for example, 1, 10, 45, 118, 412 work nicely.
See code here: http://pastebin.com/m6e78d3ce
Robert
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