sys.path[0] returns none

On Fri, Feb 5, 2010 at 5:36 PM, Spoorthi <spoorthi...@gmail.com> wrote:

> sys.path[0] should be serving the purpose effectively I guess
>
>
> On Fri, Feb 5, 2010 at 5:29 PM, Rohit Roger$ <rohitraj...@gmail.com>wrote:
>
>> Answer :
>>  >>> import sys
>> >>> rohit = sys.argv[0]
>> >>> print rohit
>>  it returns the name of the path
>>
>> On Fri, Feb 5, 2010 at 4:13 PM, David Hutto <dwightdhu...@yahoo.com>wrote:
>>
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>>>
>>> --- On *Fri, 2/5/10, nikunj badjatya <nikunjbadja...@gmail.com>* wrote:
>>>
>>>
>>> From: nikunj badjatya <nikunjbadja...@gmail.com>
>>> Subject: [Tutor] python function to know the path of the program in
>>> execution
>>> To: tutor@python.org
>>> Date: Friday, February 5, 2010, 5:08 AM
>>>
>>> Hi ,
>>> Is there any python function to know the path of the python program under
>>> execution.?
>>> If someone executes a program , he should come to know the path of the
>>> program..!!
>>> ex. suppose a user ABC is running prog.py which is in ~ directory, the
>>> user currently is in XYZ directory.
>>> [ a...@localhost XYZ ]$ python ~/prog.py
>>> The program's location is ~/prog.py
>>>
>>> This should be the outcome of the program.
>>>
>>> I tried with os.getcwd()
>>> os.getcwd() will return /path/to/folder/XYZ.
>>>
>>> Any suggestions?
>>>
>>> Thanks,
>>> Nikunj Badjatya
>>> Bangalore, India
>>>
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>>>
>>> I think this is what you want:
>>>
>>> >>> import sys
>>> >>> sys.argv[0]
>>> 'C:\\Python26\\testingscripts\\lowdir.py'
>>> >>>
>>>
>>> David
>>>
>>>
>>>
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>>
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>
>
> --
> Spoorthi
>
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