Date: Fri, 5 Feb 2010 17:43:37 +0530
From: Spoorthi <spoorthi...@gmail.com>
To: "Rohit Roger$" <rohitraj...@gmail.com>
Cc: tutor <tutor@python.org>
Subject: Re: [Tutor] python function to know the path of the program
in execution *
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<6c9f52051002050413o57bd76bax7ac5986b17304...@mail.gmail.com>
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The below data(in blue) made me converge upon sys.path[0] for this
particular problem...I dont think it returns None if a Python script is
used. Can anyone please correct me if I am wrong
*As initialized upon program startup, the first item of this list, path[0],
is the directory containing the script that was used to invoke the Python
interpreter. If the script directory is not available (e.g. if the
interpreter is invoked interactively or if the script is read from standard
input), path[0] is the empty string, which directs Python to search modules
in the current directory first. Notice that the script directory is inserted
before the entries inserted as a result of PYTHONPATH.*
On Fri, Feb 5, 2010 at 5:38 PM, Rohit Roger$ <rohitraj...@gmail.com> wrote:
sys.path[0] returns none
On Fri, Feb 5, 2010 at 5:36 PM, Spoorthi <spoorthi...@gmail.com> wrote:
sys.path[0] should be serving the purpose effectively I guess
On Fri, Feb 5, 2010 at 5:29 PM, Rohit Roger$ <rohitraj...@gmail.com>wrote:
Answer :
>>> import sys
rohit = sys.argv[0]
print rohit
it returns the name of the path
On Fri, Feb 5, 2010 at 4:13 PM, David Hutto <dwightdhu...@yahoo.com>wrote:
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--- On *Fri, 2/5/10, nikunj badjatya <nikunjbadja...@gmail.com>* wrote:
From: nikunj badjatya <nikunjbadja...@gmail.com>
Subject: [Tutor] python function to know the path of the program in
execution
To: tutor@python.org
Date: Friday, February 5, 2010, 5:08 AM
Hi ,
Is there any python function to know the path of the python program
under execution.?
If someone executes a program , he should come to know the path of the
program..!!
ex. suppose a user ABC is running prog.py which is in ~ directory, the
user currently is in XYZ directory.
[ a...@localhost XYZ ]$ python ~/prog.py
The program's location is ~/prog.py
This should be the outcome of the program.
I tried with os.getcwd()
os.getcwd() will return /path/to/folder/XYZ.
Any suggestions?
Thanks,
Nikunj Badjatya
Bangalore, India
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I think this is what you want:
import sys
sys.argv[0]
'C:\\Python26\\testingscripts\\lowdir.py'
David
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--
Spoorthi
--
Spoorthi
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------------------------------
I remember using the __file__ attribute in Django once. I don't know if
that's what you are looking for. You might want to take a loook at
http://pyref.infogami.com/__file__
HTH
Daniel
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