On Thu, Feb 11, 2010 at 4:44 AM, Stefan Behnel <stefan...@behnel.de> wrote:
> 2) given that you have lists as items in the 'data' list, it's enough to > call sort() once, as the comparison of lists is defined as the comparison > of each item to the corresponding item of the other list. If you want to > sort based on the second item before the first item, it's best to exchange > both items before sorting and swap them back afterwards. No, that is the old decorate-sort-undecorate idiom which has been replaced by the key= parameter to sort. data.sort(key=operator.itemgetter(1)) is the best way to sort on the second item. Kent _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
