Steven D'Aprano wrote:
> And for guru-level mastery, replace to call to dict.__init__ with ...
nothing at all, because dict.__init__ doesn't do anything.
>
>
>
(Sorry, should have sent to list).
I don't understand this - it must do something:
class MyDict1(dict):
def __init__(self, *args, **kw):
pass
class MyDict2(dict):
def __init__(self, *args, **kw):
dict.__init__(self, *args, **kw)
d = MyDict1(y=2)
print d
{}
d = MyDict2(y=2)
print d
{'y': 2}
d = MyDict1({'x': 3})
print d
{}
d = MyDict2({'x': 3})
print d
{'x': 3}
Behaviour is different depending on whether you call the superclass
__init__ or not.
?
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