On 6/11/10, Ken G. <beach...@insightbb.com> wrote: > I have been working on this problem for several days and I am not making > any progress. I have a group of 18 number, in ascending order, within a > list. They ranged from 1 to 39. Some numbers are duplicated as much as > three times or as few as none. FYI, Python's "set" data type will let you have a list and never have a repeat. I know that is not your goal now, but if you want to remove duplicates, it seems like a good choice. > > I started with one list containing the numbers. For example, they are > listed as like below: > > a = [1, 2, 3, 3, 4] > > I started off with using a loop: > > for j in range (0, 5): > x = a[0] # for example, 1 > > How would I compare '1' with 2, 3, 3, 4? > > Do I need another duplicated list such as b = a and compare a[0] with > either b[0], b[1], b[2], b[3], b[4]? > > Or do I compare a[0] with a[1], a[2], a[3], a[4]? A couple points here. First, you will want to make life easier by saying range(0, len(a)) so that the loop will work no matter the size of a. Second, for comparing a list to itself, here is a rather inefficient, though simple, way:
for i in range(0, len(a)): x=a[i] for j in range(0, len(a)): y=a[j] if(x==y and i!=j): #match since a[i]==a[j] and i and j are not the same index of a > > In any event, if a number is listed more than once, I would like to know > how many times, such as 2 or 3 times. For example, '3' is listed twice > within a list. Do not quote me here, but I think sets may be able to tell you that as well. > > TIA, > > Ken > > > > > > > > > _______________________________________________ > Tutor maillist - Tutor@python.org > To unsubscribe or change subscription options: > http://mail.python.org/mailman/listinfo/tutor > -- Have a great day, Alex (msg sent from GMail website) mehg...@gmail.com; http://www.facebook.com/mehgcap _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
