On Wed, 23 Jun 2010 10:29:11 pm Nethirlon . wrote:
> Hello everyone,
>
> I'm new at programming with python and have a question about how I
> can solve my problem the correct way. Please forgive my grammar,
> English is not my primary language.
>
> I'm looking for a way to repeat my function every 30 seconds.
The easiest way is to just run forever, and stop when the user
interrupts it with ctrl-D (or ctrl-Z on Windows):
# untested
def call_again(n, func, *args):
"""call func(*args) every n seconds until ctrl-D"""
import time
try:
while 1:
start = time.time()
func(*args)
time.sleep(n - (time.time()-start))
except KeyboardInterrupt:
pass
Of course, that wastes a lot of time sleeping.
As an alternative, you need to look at threads. That's a big topic, you
probably need to read a How To or three on threads.
In the meantime, here are a couple of recipes I found by googling. I
have no idea of they are good or not.
http://code.activestate.com/recipes/576726-interval-execute-a-function/
http://code.activestate.com/recipes/65222-run-a-task-every-few-seconds/
> As an example I have written a ping function. But I would like this
> function to repeat itself every 30 seconds, without stopping until I
> give it a STOP command (if such a thing exists.)
>
> Code:
> import os, sys
>
> def check(host):
> try:
> output = os.popen('ping -ns 1 %s' % host).read()
> alive = output.find('Reply from')
> print alive
> if alive is -1:
> print '%s \t\t DOWN ' % host
> else:
> print '%s \t\t OK' % host
> except OSError, e:
> print e
> sys.exit()
Why are you catching the exception, only to print it and exit? Python
does that automatically. This much easier, and doesn't throw away
useful information:
def check(host):
output = os.popen('ping -ns 1 %s' % host).read()
alive = output.find('Reply from')
print alive
if alive is -1:
print '%s \t\t DOWN ' % host
else:
print '%s \t\t OK' % host
--
Steven D'Aprano
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