Hello Alan,
> First please start new threads wirth a new email, do not reply to
thought i did, my apologies.
> "eMyListsDDg" <emylists...@gmail.com> wrote
> First please start new threads wirth a new email, do not reply to
> a previous post - it confuses threaded readers. (and sometimes
> human readers too!)
>> '\x00\x11\xb2\x00@,O\xa4'
>> the above str is being returned from one key/value pair in
>> a dictionary. it is the addr of a network device.
>> i want to store the addr's in their 8byte mac format like this,
>> [00 11 b2 00 40 2C 4F A4]
> Thats what you've got. The string is merely a representation
> of that data.
>> the combinations of format strings using the print statement
>> hasn't resulted in what i need.
> format strings are used to display data not to store it.
> Do you really want to display the data in the format you've
> shown? Or do you really want to store it as 8 bytes?
the format shown. now that you point out a few things, it really wouldn't
matter.
> The two concepts are completely different and more
> or less unrelated.
i see that now, as a newbie to python.
>> looking for a suggestion on how to format this,
>> '\x00\x11\xb2\x00@,O\xa4' into this [00-11-B2-00-40-2C-4F-A4]
> OK, to display it you need to extract each byte and convert it to
> a string representing the hex value. Fortunately you an treat a
> string of bytes as charactrers and the hex() function will give you
> the hex representation. So...
> print "[%s]" % ('-'.join([hex(v) for v in theValue]) )
helps me to understand the concept differences you pointed out better
appreciate the help...
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