2010/7/28 Dave Angel <da...@ieee.org>
>
>
> ZUXOXUS wrote:
>
>> Oh, I think i got it:
>>
>>
>>
>>> for prod in itertools.product('ABC', 'ABC'):
>>>>>
>>>>>
>>>> print(prod)
>>
>> ('A', 'A')
>> ('A', 'B')
>> ('A', 'C')
>> ('B', 'A')
>> ('B', 'B')
>> ('B', 'C')
>> ('C', 'A')
>> ('C', 'B')
>> ('C', 'C')
>>
>> Thank you very much!!
>>
>> 2010/7/28 ZUXOXUS <zuxo...@gmail.com>
>>
>>
> You're top-posting, which loses all the context. In this forum, put your
> comments after whatever lines you're quoting.
>
> Your latest version gets the product of two. But if you want an arbitrary
> number, instead of repeating the iterable ('ABC' in your case), you can use
> a repeat count. That's presumably what you were trying to do in your
> earlier incantation. But you forgot the 'repeat' keyword:
>
> for prod in itertools.product('ABC', repeat=4):
> xxxx
>
> will give you all the four-tuples.
>
> DaveA
>
>
>
> Hey
>
Sorry for the top-posting, I forgot this rule
Thanks for the reminder, Dave Angel, and for the 'repeat' keyword!
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