"David Hutto" <smokefl...@gmail.com> wrote
To check it states that the answer should be app. 10**18kg However,
and I've checked to make sure that the math I've layed out matches
up
with the texts, I get 5.07360705863e+20
A couple of comments but my Physics is a bit rusty!!
import math
def atmosphereWeight():
pi = math.pi
"""Air Pressure (at sea level) P0. This is the long-term average.
P0 = 1.01325 × 10**5"""
You can express scientific notaton directly:
airPressCLevl = 1.01325*(10**5)
airPressCLevl = 1.01325e5
gravity = 9.82
It was 9.81 when I was at school.
Doubt if that accounts for the difference though...
"""We can use g to get the kg of mass from the force of air
pressure P0. Apply the acceleration of gravity
(in m/sec2) to the air pressure (in kg · m/sec2).
I'd expect pressure to be in Pa or N/m2 or (Kg*m/s2)/m2 = Kg/ms2?
mass of the atmosphere in kilograms per
square meter (kg/m2).
Mm2 = P0 × g"""
masAtmoInKgPerSqM = airPressCLevl * gravity
So I'd expect P0/g?
"""Given the mass of air per square meter, we need to know how
many square meters of surface to apply
this mass to. Radius of Earth R in meters, m. This is an average
radius; our planet isn’t a perfect sphere.
R = 6.37 × 10"""
avgRadiusEarth = 6.37 * (10**6)
I assume the comment's exponent is wrong?! :-)
"""The area of a Sphere.
A = 4πr2"""
areaSphere = 4 * pi * (avgRadiusEarth**2)
"""Mass of atmosphere (in Kg) is the weight per square meter,
times the number of square meters
Ma = P0 × g × A"""
masEarthAtmoInKgPerSqM = airPressCLevl * gravity * areaSphere
Why don't you use the value you calculated above?
Now if you divide by 10 instead of multiplying by 10 you get a
different of 2 in the exponent?
print(masEarthAtmoInKgPerSqM)
HTH,
--
Alan Gauld
Author of the Learn to Program web site
http://www.alan-g.me.uk/
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