Hello, 

 

Oke, the 4 is a starting point for the index.

 

Next problem.

 

The begin looks like this :

 

 index_of(5, (1, 2, 4, 5, 6, 10, 5, 5), 4)


But in the module I get this result :

 

val = 5

seq = (1, 2, 4, 5, 6, 10, 5, 5

 

So the 4 is not avaible anymore.

 

Now I can change the header to  index(val, seq, start=0) to index (val, seq, 
start)

But I think that's not what the exercise wants.

 

Is there another way I can use the 4 ?

 

Roelof

 


 
> To: tutor@python.org
> From: alan.ga...@btinternet.com
> Date: Mon, 6 Sep 2010 23:28:22 +0100
> Subject: Re: [Tutor] exercise correct ??
> 
> 
> "Roelof Wobben" <rwob...@hotmail.com> wrote
> 
> #################
> def index_of(val, seq, start=0):
> """
> >>> index_of(5, (1, 2, 4, 5, 6, 10, 5, 5), 4)
> 6
> """
> 
> But I get this message :
> Failed example:
> index_of(5, (1, 2, 4, 5, 6, 10, 5, 5), 4)
> Expected:
> 6
> Got:
> 3
> #####################
> 
> > But in that tuple 5 is on position 3.
> > Is the exercise here wrong ?
> 
> No because the start position is 4 so you don;t see the 5 in position 
> 3.
> 
> HTH,
> 
> -- 
> Alan Gauld
> Author of the Learn to Program web site
> http://www.alan-g.me.uk/
> 
> 
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