On Sat, 2 Oct 2010 01:14:27 am Alex Hall wrote: > >> Here is my test: > >> s=re.search(r"[\d+\s+\d+\s+\d]", l) > > > > Try this instead: > > > > re.search(r'\d+\s+\D*\d+\s+\d', l) [...] > Understood. My intent was to ask why my regexp would match anything > at all.
Square brackets create a character set, so your regex tests for a string that contains a single character matching a digit (\d), a plus sign (+) or a whitespace character (\s). The additional \d + \s in the square brackets are redundant and don't add anything. -- Steven D'Aprano _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
