Thanks for your replies, and reminding me of statistics(probably a quick crash course). The data I plan to use would be equally charted by a constant timestep in it's movement(type of movement graphed being dictated by the object being measured)
So I thought that maybe the easiest way would be something like the following: a = ['+','-','+','-','+','-','+','-','+','-','+'] b = ['-','+','-','+','-','-','-','+','-','-','-'] count = 0 lena = len(a) lenb = len(b) if lena == lenb: for num in range(0,lena): if a[num] == b[num]: print 'match' count += 1 else: print 'Lists are not same length for comparison' per = (100/lena) print count * per, '% match' The plus and minus signs would represent the movement over an equal amount of time(say one minute/hour) Although I'm going to the statistics for the rest of this, anyone who has an improved solution let me know. Thanks, David _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor