> @Evert, I didn't figure out that your response was a solution, thought it was > a question. Must be coffee time :P > > I tried it and, for instance, the rounded value (9) / 2 gave me 4.0 Couldn't > get it until I noticed that @Joel divided the roudned figure by a decimal > 2.0. That gave 4.5, which is what I was looking for.
How do you get a rounded value of 9 (integer)? Round() returns a float, afaik; ie, you wouldn't the the 2.0, but just 2. (In fact, your return value is 4.0, which for integer division wouldn't work. So something was odd there, but I can't think of what.) Also, perhaps better to use from __future__ import division to prevent these mistakes. Cheers, Evert > > I realise that one cannot have a half integer :) I meant how would one > > round off to the first decimal nearest to either 0.5, or a whole number. > > > > Ugh...does anyone get what I'm trying to articulate? :) > > Multiply by 2, round(), divide by 2? > > That sounds like a good idea: > > >>> n = [1.0 + x/10.0 for x in range(10)] # get some numbers to test > >>> n > [1.0, 1.1000000000000001, 1.2, 1.3, 1.3999999999999999, 1.5, > 1.6000000000000001, 1.7, 1.8, 1.8999999999999999] > >>> r = [round(2*x)/2.0 for x in n] # double, round, then divide by 2.0 > >>> r > [1.0, 1.0, 1.0, 1.5, 1.5, 1.5, 1.5, 1.5, 2.0, 2.0] > >>> > > > -- > Joel Goldstick > > > _______________________________________________ > Tutor maillist - Tutor@python.org > To unsubscribe or change subscription options: > http://mail.python.org/mailman/listinfo/tutor > > > > > -- > Regards, > Sithembewena Lloyd Dube > http://www.lloyddube.com > _______________________________________________ > Tutor maillist - Tutor@python.org > To unsubscribe or change subscription options: > http://mail.python.org/mailman/listinfo/tutor _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
