On 11/28/2010 10:57 AM, Emile van Sebille wrote:
On 11/28/2010 7:55 AM John Smith said...
Can anybody tell me why the handle below is invalid? I'm running Win7.
TIA,
John
Python 2.7 (r27:82525, Jul 4 2010, 07:43:08) [MSC v.1500 64 bit (AMD64)]
on win32
Type "copyright", "credits" or "license()" for more information.
>>> import serial
>>> ser = serial.Serial('com1', timeout = 5)
What do you get when you add 'print ser' here? The docs at
http://pyserial.sourceforge.net/shortintro.html show you should get
something like
Serial<id=0xa81c10, open=False>(port='COM1', baudrate=19200, bytesize=8,
parity='N', stopbits=1, timeout=None, xonxoff=0, rtscts=0)
So if you're getting an invalid handle error I'd expect you'd get
something different.
Emile
Hi, Emile -
Okay. Here it is:
>>> print ser
Serial<id=0x224c240, open=True>(port='COM1', baudrate=9600, bytesize=8,
parity='N', stopbits=1, timeout=5, xonxoff=False, rtscts=False,
dsrdtr=False)
>>>
Thanks.
John
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