On Sun, Dec 19, 2010 at 4:57 PM, Alan Gauld <alan.ga...@btinternet.com> wrote:
>
> "lei yang" <yanglei.f...@gmail.com> wrote
>
>
> def runForAWhile(cmd, secs=10):
> print("running %s" % cmd)
> timeout = datetime.timedelta(seconds=secs)
> print timeout
> proc = subprocess.Popen(cmd, stdout=subprocess.PIPE,
> stderr=subprocess.STDOUT, shell=True)
> status = proc.poll()
>
> You are still only checking status once outside the while loop.
>
Thanks, I make a stupid mistaking
Lei
> start = datetime.datetime.now()
> while (status is None and (datetime.datetime.now() - start) <
> timeout): #not timed out
> print proc.stdout.readline() #TODO timestamp?
> #print status
> #print datetime.datetime.now() - start
>
>
>> I see that "status" always "!=0“ why program is NOT exited
>
>
> --
> Alan Gauld
> Author of the Learn to Program web site
> http://www.alan-g.me.uk/
>
>
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