You should have a comma after the "#" in the highlighted print statement, that
should repress the new line (I'm guessing that's the line you're talking about)
print >> f,t,"#",
Jason
..·><((((º>
-----Original Message-----
From: tutor-bounces+jasons=adventureaquarium....@python.org
[mailto:tutor-bounces+jasons=adventureaquarium....@python.org] On Behalf Of
Tommy Kaas
Sent: Wednesday, January 12, 2011 10:40 AM
To: tutor@python.org
Subject: [Tutor] how avoid writing a newline?
I'm using Activepython 2.6.6 on PC/Win7
I have made a small scraper script as an exercise for myself.
It scrapes the name and some details of the first 25 billionaires on
the Forbes list.
It works and write the result in a text file, with the columns
separated by "#"
It takes the name from the link (t = i.string) - open the link and
scrape details from the next page.
But I can't find a way to write the name (the variable t) one and only
one time in the beginning of the line.
As t is written now I get it in the beginning of the line but I also
get a newline.
Can I avoid that in a simple way?
Thanks in advance for any help
Tommy
from BeautifulSoup import BeautifulSoup
from mechanize import Browser
f = open("forbes.txt", "w")
br = Browser()
url =
"http://www.forbes.com/lists/2010/10/billionaires-2010_The-Worlds-Billionaires_Rank.html";
page = br.open(url)
html = page.read()
soup = BeautifulSoup(html)
table = soup.find("table")
l = table.findAll('a')
for i in l[5:]:
t = i.string
print t #to the monitor
br.follow_link(text_regex=r"(.*?)"+t+"(.*?)")
tekst = br.response().read()
soup = BeautifulSoup(tekst)
table1 = soup.find('table', id='billTable')
rows = table1.findAll('tr')
print >> f, t,"#"
for tr in rows:
tds = tr.findAll(text=True)
print >> f, tds[1].string,"#",tds[2].string,"#",
print >> f, '\r\n'
f.close()
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