Hi guys,
Please help me with this:
Convert an IP address from binary string to decimal format.There are
some preconditions:
1.IP address is in the form of '000010010....001100'.32 bits with no dot.
2.int(string, base) is not allowed, You have to implement the conversion .
3.Performance should be considered.
For example an IP address like '11111111111111111111111111111111 '
would be converted to '255.255.255.255'
That's how I implement it. But I think it looks ugly and I wonder if
there is a better way to do this.
import re
import sys
def convert(bin_ip):
patt = re.compile(r'\d{8}')
bin_list = patt.findall(str(bin_ip))
dec_list = []
for bin in bin_list:
sum = 0
i = 7
for n in bin:
if int(n):
sum = sum + 2**i
i = i - 1
dec_list.append(str(sum))
dec_ip = '.'.join(dec_list)
print dec_ip
if __name__ == '__main__':
bin_ip = sys.argv[1:]
convert(bin_ip)
Thanks in advance and excuse my poor English.
Best regards,
Tom
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