Thanks Ian!
This is a simple one!
I found this other way said more flexible, I must check it too:
*import urllib
class myURLOpener(urllib.FancyURLopener):
def setpasswd(self, user, passwd):
self.__user = user
self.__passwd = passwd
def prompt_user_passwd(self, host, realm):
return self.__user, self.__passwd
urlopener = myURLOpener()
urlopener.setpasswd("mulder", "trustno1")*
Basically, we must subclass **urllib.FancyURLopener** and override
**prompt_user_passwd().
**Regards
Karim
**
** On 01/28/2011 11:15 PM, ian douglas wrote:
If it's HTTP basic_auth, you could try this method too:
http://username:passw...@domain.com/page.html
On 01/28/2011 01:54 PM, Karim wrote:
Hello,
I want to create a client to access a webpage. But when I access it
interactively there is a dialog box
which ask for login and password.
I want to access it in batch via python but I could only found a
basic example:
||#||!/bin/env|| ||python|
|#|| ||-*-|| ||coding:|| ||utf-8|| ||-*-|
|import| urllib2
reponse|=| urllib2.|urlopen|(|'||http||:||/||/||www||.||kernel||.||org||/||'|)
xhtmldata|=| reponse.|read|()
|for| num,ligne|in| |enumerate|(xhtmldata.|splitlines|()) :
|print| |"||%04d|| ||-|| ||%s||"||%|(num,ligne)
|
I want to provide login and password via python code. The web adress
is like http://website.com:8081/ddts/ddts_main.
If you have link it is welcome!
Regards
Karim
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