On Thu, Feb 24, 2011 at 3:03 PM, tee chwee liong <tc...@hotmail.com> wrote: >>>> '0x' + hex(543)[2:].zfill(5) > '0x0021f' > > this is a good way but it's still in string format. but if i convert it to > long, then the leading 0s will be truncated. i guess can't have it both way.
A long is just a number. You cannot say that a number has or does not have leading zeroes. Only _a representation of_ that number has. The numbers 3, 1+2 and 0000000000003 are all the same number, so you cannot say that the first does not have leading zeroes whereas the last one has. To make the concept of 'leading zeroes' a meaningful one, you _first_ have to re-convert the number to a string. Whether or not there are leading zeroes depends on how that conversion is done. If you use Python's standard conversion method, the result will be a string representation without leading zeroes, but there are other conversion methods that do give leading zeroes. -- André Engels, andreeng...@gmail.com _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
