-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 On 05/01/2011 02:28 PM, Greg Christian wrote: > Is there a way to write an if statement that will pick up duplicates (two > ‘1’s): > > L = ['1', '4', '1'] > if (L[0]) != (L[1]) != (L[2]): > print "THEY ARE NOT EQUAL" > else: > print "THEY ARE EQUAL" > > When I run this code, it prints “THEY ARE NOT EQUAL” when it should print the > else “THEY ARE EQUAL”. >
Well, think about what that if-statement is doing. It's making sure that the first three elements of L aren't equal to each other. Due to python's short-circuit evaluation, it breaks the if after the first one, because '1' != '4'. The parentheses there are useless. You might look at [1] to see if there is anything that will count how many times something appears in a list... [1] -- http://docs.python.org/tutorial/datastructures.html#more-on-lists - -- Corey Richardson -----BEGIN PGP SIGNATURE----- Version: GnuPG v2.0.17 (GNU/Linux) Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org/ iQEcBAEBAgAGBQJNvav2AAoJEAFAbo/KNFvpx/IH/iT54cNeVSSJsRQit13Hf91H y6zy9Cx3pE9Pxf+crK+9tT53C67TxQIdLRcD83fuXF1iEZJYwVlgQv5Py7U7KIy2 X0SU9ScL4xy/b3k8QB+kj7w7wt4Aa0yPhAx6mZI0KXErj6hVjeIljQf6E3irY7K1 Uot5TY5vY6YieKX+Sc/C2Kv3nmPCM2x1TcuwzX+zIGFBNEuGDb1jNdTR8LkVG+nb WqBPEtO5sEy9/5NULtExSgS80xUT/fLCRc6gpf5yQBIi/xm+lOBTx1hUCgYfrsLp gCKOIrXtPaI1bYdxf2tApDUWXVAe5U7tB9z4s9Uz9bV3x8od2w5gsCmxLLJgLHs= =Sz54 -----END PGP SIGNATURE----- _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor