unsubscribe
在 2011-06-08 07:11:33，"Walter Prins" <wpr...@gmail.com> 写道： Hi, 2011/6/7 Válas Péter<suli...@postafiok.hu> Hi, let X be a mutable container, such as dict/set/list=bytearray, and Y=X, When I change X, Y will follow it, having always the same value, although id(X)!=id(Y). That's not correct: Python 2.7 (r27:82525, Jul 4 2010, 07:43:08) [MSC v.1500 64 bit (AMD64)] on win 32 Type "help", "copyright", "credits" or "license" for more information. >>> x=[1,2,3] >>> y=x >>> id(x) 36115464L >>> id(y) 36115464L >>> x.append(4) >>> id(x) 36115464L >>> id(y) 36115464L >>> x [1, 2, 3, 4] >>> As you can see, x and y are references to the same object (e.g. with the same id.) Regards Walter
_______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
