Well, that's a trick me and jake learned in a book to stop the program
from changing.
On Saturday, June 18, 2011, aditya <nauty.m...@gmail.com> wrote:
>
>
> On Sat, Jun 18, 2011 at 9:35 PM, Jacob Bender <benderjaco...@gmail.com> wrote:
>
> Dear Tutors,
>
> Alright, I'm using linux (ubuntu) and I took all of your advice and I got
> something that works and doesn't work at the same time. Here's the source
> code for my two programs called Lock and Key:
>
> Lock.py:
>
> password = "a"
>
>
> psswd_try = raw_input("What's the password? ")
>
>
> if psswd_try == password:
>
> print "correct!!!"
>
> raw_input()
>
> else:
>
> print "wrong"
>
> raw_input()
>
> Why do you need to call raw_input() again? You are giving the input only
> once so remove raw_input() from both if and else , that should do the work
>
> Key.py:
>
> import sys
>
>
> sys.stdout.write("a")
>
> In the linux terminal I ran this command(they were both in my home folder, so
> no directories were needed):
>
> python Key.py | python Lock.py
>
> And all went well except for an EOF error caused by the raw_input inside the
> "if" statement in my Lock program. However I did get it to print "correct",
> so I know sys.stdout.write() works for what I want it to, but I don't want
> the EOF error. Here's the output:
>
> Traceback (most recent call last):
> File "Lock.py", line 7, in <module>
> raw_input()
> EOFError: EOF when reading a line
>
> Please help me get rid of it because I couldn't find a sys.stdout.close()
> command or any other std command that would help.
>
> Thanks!
>
>
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>
>
> --
> RegardsAditya
>
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