Thanks for that Donald! -Alex
On Wed, Jul 27, 2011 at 8:16 PM, Donald Wilson <donald...@me.com> wrote: > You could start with an anonymous function using the lambda operator, such > as: > > ------------------------------------------------------------ > > mid_range = lambda x: x[len(x) // 2] > > Note: If you use len(x) / 2 in python 3.x you will get a TypeError because > the division operator / returns a float. Floor // returns an int in 2.x and > 3.x. > > Then use either: > > x = range(1000, 4001) > mid_x = mid_range(x) # mid_x == 2500 > > or… > > mid_x = mid_range(range(500, 751)) # mid_x == 625 > > etc. to retrieve the middle element. > > You can extract the mid point of any sequence type, such as a string, using > this function. > > mid_x = mid_range(‘12345678987654321’) # mid_x == ‘9’ > > ------------------------------------------------------------ > > middle_number = lambda lo, hi: abs(lo - hi) // 2 > > will work if you just need the mid point of two numbers; either ints or > floats. > > mid_x = middle_number(0, 1000) # mid_x = 500 > > DW > > On Jul 27, 2011, at 8:16 PM, Alexander Quest wrote: > > > Does anyone know how to assign a certain numerical range to a variable, > and then choose the number that is the middle of that range? For example, I > want to assign the variable "X" a range between 1 and 50, and then I want to > have the middle of that range (25) return with some command when I call it > (perhaps rangemid or something like that?). In pseudocode, I am trying to > say X = range [1,50], return middle of range (which should return 25) but I > don't know how to code it. This is for a basic program I'm trying to write > where the player thinks of a number and the computer tries to guess the > number in as few tries as possible. Thanks for any help! > > > > -Alex > > _______________________________________________ > > Tutor maillist - Tutor@python.org > > To unsubscribe or change subscription options: > > http://mail.python.org/mailman/listinfo/tutor > > _______________________________________________ > Tutor maillist - Tutor@python.org > To unsubscribe or change subscription options: > http://mail.python.org/mailman/listinfo/tutor >
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