On 10/04/2011 01:09 PM, lina wrote:
But I still don't know how to get the
statistic result of each column,
Thanks for further suggestions,
Best regards,
lina
As I said before, your current code counts across a line at a time,
while you need to count vertically. That could be done by transposing
the list of strings, but it's probably easier to just count them
yourself. So set up a list of counters, all zero, and every time you
see a desired character, increment the corresponding counter.
Here's the existing code:
#!/bin/python
import os.path
tokens=['B','E']
for fileName in os.listdir("."):
result=[]
if os.path.isfile(fileName) and os.path.splitext(fileName)[1]==".xpm":
filedata = open(fileName)
text=filedata.readlines()
for line in text[0:]:
result.append({t:line.strip().count(t) for t in tokens})
for index,r in enumerate(result):
outfiledata=open("fileName.txt","w")
Decide first on a reasonable data arrangement for the results. I'd suggest
having a map of lists, rather than the other way around.
So initialize it to having zeroes in all the right places.
results = {}
numcolumns = len(text[23].strip())
for ch in tokens:
results[ch] = [0] * numcolumns
and
for line in text[23:]:
for col, ch in enumerate(line):
if ch in tokens:
results[ch][col] += 1
(Untested)
--
DaveA
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