On 10/28/2011 01:38 AM, Praveen Singh wrote:
splitWord('google', 2)
['go', 'og', 'le']
>>> splitWord('google', 3)
['goo', 'gle']
>>> splitWord('apple', 1)
['a', 'p', 'p', 'l', 'e']
>>> splitWord('apple', 4)
['appl', 'e']
def splitWord(word, number):
length=len(word)
list1=[]
x=0
increment=number
while number<=length+increment:
list1.append(word[x:number])
x=x+increment
number=number+increment
for d in list1:
if d=='':
list1.remove('')
return list1
I am getting the desired output and this code is working fine..but i
think it is quite bulky for this small operation.
qus.1-- can you guys suggest me some better solution??
qus 2-- i know writing just a piece of code is not going to help me. i
have to write efficient code.i want to know how to calculate execution
time of my code and
can you guys suggest me some links so that i can learn how to
find complexity of code??
Thanks in advance...
Use the grouper() recipe, shown on the intertools page of the docs:
http://docs.python.org/library/itertools.html
--
DaveA
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