you are spot on......... thanks very much i understand the problem now and its
been solved.
very clear help
thanks, adrian
> Date: Thu, 17 Nov 2011 14:01:19 -0500
> From: d...@davea.name
> To: kellyadr...@hotmail.com
> CC: tutor@python.org
> Subject: Re: [Tutor] local variable referenced before assignment
>
> On 11/17/2011 01:47 PM, ADRIAN KELLY wrote:
> > hi all,keep getting the above error, can't understand or fix it, can anyone
> > help.
> > def exchange(): euro=1 dollar=1.35 base=50 amount = input ('how
> > much do you want to change') if amount>base:
> > totalreturn=amount*dollar else: print 'not enough' return
> > totalreturn
> > print exchange()
> >
> >
> You've been doing better, but this one has lost its formatting
> entirely. Are you posting in text mode?
>
> That's not the entire error message. If you examined the entire
> traceback, it'd identify the line with the problem, and the particular
> variable that's being used before it's been defined.
>
>
> But since the function is small, i can guess my way through. The
> variable is apparently "totalreturn". And when you go through the else
> clause you completely miss the assignment to it. When you have a
> mechanism like:
>
> if x > y:
> newval = 49
> else:
> print "error message"
> #newval = -5
> return newval
>
> Without that second assignment, you'll get "the above error" whenever
> the else condition prevails. newval has no value, and in fact doesn't
> exist if you go through the else clause.
>
>
> --
>
> DaveA
>
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