On 12/08/2011 04:27 PM, bod...@googlemail.com wrote:
That won't work because l1[0] is ['a', 1]
What happens if you don't change the code?
l1.index('c')
Bodsda
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-----Original Message-----
From: Robert Berman<berma...@cfl.rr.com>
Sender: tutor-bounces+bodsda=googlemail....@python.org
Date: Thu, 08 Dec 2011 16:13:32
To: tutor<tutor@python.org>In [1]: l1=[['a',1],['b',2],['c',3]]
In [2]: l1
Out[2]: [['a', 1], ['b', 2], ['c', 3]]
In [3]: l1.index('c')
---------------------------------------------------------------------------
ValueError Traceback (most recent call last)
/home/bermanrl/<ipython console> in<module>()
ValueError: 'c' is not in list
Subject: [Tutor] list.index() question
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Bodsa et al,
What happens is as follows:
In [1]: l1=[['a',1],['b',2],['c',3]]
In [2]: l1
Out[2]: [['a', 1], ['b', 2], ['c', 3]]
In [3]: l1.index('c')
---------------------------------------------------------------------------
ValueError Traceback (most recent call last)
/home/bermanrl/<ipython console> in <module>()
ValueError: 'c' is not in list
I really appreciate the help I am getting. Eventually I am certain there
is a relatively easy solution I simply do not have the expertise to see it.
Robert
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