On Fri, Dec 23, 2011 at 8:19 PM, Andreas Perstinger <andreas.perstin...@gmx.net> wrote: > On 2011-12-23 12:02, lina wrote: >> >> for i in range(len(result)): >> for j in range(len(result[i])): >> print(result[i][j]) >> >> still have a little problem about print out, >> >> I wish to get like >> a a >> b b >> c c >> which will show in the same line, >> >> not as >> a >> b >> c >> a >> b >> c > > > So you wish to print all the first elements from your sublists on the first > line, all the second elements on the second line, and so on, right? yes. > > Python 3.2 (r32:88445, Mar 25 2011, 19:28:28) > [GCC 4.5.2] on linux2 > Type "help", "copyright", "credits" or "license" for more information. >>>> result = [["a1", "b1", "c1"],["a2", "b2", "c2"],["a3", "b3", "c3"]] >>>> for i in zip(*result): > ... print(" ".join(i)) > ... > a1 a2 a3 > b1 b2 b3 > c1 c2 c3 > > Explanation: > "zip()" takes an arbitrary number of iterables and "returns an iterator of > tuples, where the i-th tuple contains the i-th element from each of the > argument sequences or iterables." (see the docs on > http://docs.python.org/py3k/library/functions.html#zip): > >>>> print(list(zip([1, 2, 3], [4, 5, 6]))) > [(1, 4), (2, 5), (3, 6)] > > In your case, you would have to call "zip()" with > > zip(result[0], result[1], result[2], ... result[x]) > > depending on how many files you process. > > But using the *-operator you can unpack "result" (which is a list of > sublists), so that "zip" will see all the sublists as separate arguments. > See also > http://docs.python.org/py3k/tutorial/controlflow.html#unpacking-argument-lists > > For printing you just join all the elements of one tuple to a string. > > HTH, Andreas
Thanks for all. really good suggestions. Best regards and have a weekend. > > _______________________________________________ > Tutor maillist - Tutor@python.org > To unsubscribe or change subscription options: > http://mail.python.org/mailman/listinfo/tutor _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor