Posting as HTML caused your indentation to be all wrong. Try to post as plain text to remove those errors. Thankfully your program is not very complicated.
import string def decrypt(cypheredText, shiftedCypherNumber): ''' This function will take two arguments. The first is the cyphered text, the second is the number of characters we need to shift the text so we can decrypt it. This is a Caesar cypher. ''' for letter in cypheredText: asciiValue = ord(letter) if asciiValue in range(97, 123): asciiValue += shiftedCypherNumber if asciiValue > 122: asciiValue -= 26 newLetter = chr(asciiValue) text = list() text.append(newLetter) joinedText = ' '.join(text) return joinedText text = 'g fmnc wms bgblr rpylqjyrc gr zw fylb' a = decrypt(text, 2) print a You have very little range checking which means that it is very likely to not work (or behave oddly) for unexpected values. The biggest flaw I see is that your list is created at the wrong level. It should be outside the for loop. The problem with list creation being in the for loop is that you create a new list each iteration of the for loop and what happens to the old list? You lose it. If you created the list outside the for loop and my indentation above is incorrect then you created and appended to it after finishing your for loop. This would be incorrect because what would happen to all the values calculated inside the for loop? They would be lost. Either way, it is incorrect. You should declare text before the for loop and then append to it inside the for loop. The above is why you only get one letter and also why text=list(newLetter) is incorrect for your problem. Ramit Ramit Prasad | JPMorgan Chase Investment Bank | Currencies Technology 712 Main Street | Houston, TX 77002 work phone: 713 - 216 - 5423 -- This email is confidential and subject to important disclaimers and conditions including on offers for the purchase or sale of securities, accuracy and completeness of information, viruses, confidentiality, legal privilege, and legal entity disclaimers, available at http://www.jpmorgan.com/pages/disclosures/email. _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor