Always reply-all so a copy goes to the tutor list.
On 2/8/2012 11:04 PM, Michael Lewis wrote:
Thanks Bob,
Thanks for what if you did not follow my suggestions?
Your code is still pretty buggy.
Please test it by running it, seeing that the result is not correct,
then try the desk checking.
The below code is what I came up with without using your suggestion.
On a scale, how novice is mine compared to what you offered? I am
curious because I want to know if I should have come up with your
solution instead of what I did come up with.
def AlterInput(user_input):
'''search for nums in str and increment/append, return new string'''
new_output = []
for num in user_input:
if not num.isdigit():
new_output.append(num)
else:
num.isdigit()
new_num = int(num)
new_num += 1
new_output.append(str(new_num))
return ' '.join(new_output)
def GetUserInput():
'''Get a string from the user and pass it'''
user_input = '''I * got 432 when I counted, but Jim got 433 which
is a lot for only 6 cats, or were there 12 cats?'''
return AlterInput(user_input.split())
Your code:
return ' '.join(str(int(num)+1) if num.isdigit() else num for num in
user_input)
On Wed, Feb 8, 2012 at 6:04 AM, bob gailer <bgai...@gmail.com
<mailto:bgai...@gmail.com>> wrote:
On 2/8/2012 12:56 AM, Michael Lewis wrote:
I want to find all digits in a string and then increment those
digits by 1 and then return the same string with the
incremented digits.
[snip]
You got lots of good advice from others and some not-so-good advice.
Michael said:
2. The following line appears wrong.
new_output = ' '.join(user_input)
He did not say why!
I add:
Master the art of "Desk Checking".
Take pencil & paper.
Write down the input and output of each statement as though you
were the computer.
Also learn to read the & understand the Python Manuals:
str.replace(old, new[, count])
Return a copy of the string with all occurrences of substring old
replaced by new. If the optional argument count is given, only the
first count occurrences are replaced.
Notice "return a copy". It does NOT say that this will convert old
in place.
No one else caught this problem!
Since this is homework we we probably should not be offering
alternative solutions.
However I can't resist offering the one-line solution:
''.join(str(int(x)+1) if x.isdigit() else x for x in 'user_input)
--
Bob Gailer
919-636-4239 <tel:919-636-4239>
Chapel Hill NC
--
Bob Gailer
919-636-4239
Chapel Hill NC
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